Wordpandit Question of the day
Ramu mixes 2 litres of mineral water costing Rs. 15 per litre with 18 litres of milk that he bought for Rs. 900. After selling 2 litres of this mixture to Shamu, Ramu adds tap water so that the ratio of milk to tap water is 9:10. If tap water is free and Ramu claims to sell at cost, what is his profit?
a. 92%
b. 104%
c. 113 %
d. 87%
Answers and Explanations
Answer is option b
The 2 litres given to Shamu contain milk and water in the ratio 9:1, i.e., 1.8 litres of milk and 0.2 litres of water.
The remaining 18 litres contains 16.2 litres of milk and 1.8 litres of water.
After adding tap water, the ratio of milk to water becomes 9:10. ⇒ the quantity of tap water is 16.2 × 10/9 = 18 litres.
Since the mixture already has 18 litres, the total quantity now becomes 36 litres.
The total revenue is 36 × 50 + 2 × 50 (already sold) = 1900.
The total cost is 900 + (2 × 15) = Rs. 930.
Thus, his profit is 1900 – 930 = Rs. 970 ⇒ (970/930) × 100 = 104%.
