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### Oliveboard Question of the day

If A = 200

B = A – 99

C = A + B – 98

D = A + B + C – 97 and so on upto Z.

Find the value of 2^{-25}(Z+1)

__Options:__

- 50
- 51
- 26
- None of these

#### Solution posted below. Click on the plus sign to view the solution.

### Answer and Explanation

Answer key: 2

A = 200

B = 101

C = 203

D = 407

E = 815

This way we see that for the n^{th} English alphabet (where n>1), the value is (2^{n-2} x 100) + (2^{n-1} – 1).

So, Z = (2^{24}x100) + (2^{25}-1)
So, Z + 1 = (2^{24}x100) + (2^{25}-1) + 1
= 2^{25}(50 + 1)

So, 2^{-25}(Z+1) = 2^{-25} x 2^{25}(50 + 1)

= 51

Guys, thanks for the participation..:)

We have put the solution, in case you need to understand the logic.

51

51

2^-25=1/2^25=1/33554432

value of z+1=1707081729

1/33554432*1707081729=50.8~51

50.8~ 51

51